Skip to content

… and parameter 8 too.

April 30, 2012

Tim Penttila reminded me that in my previous post, I haven’t done x=8 (since (q^2+1)/2 = 8.5). So I’ve slightly altered my program, changing the size of my putative solution to 168, and ran it again. This time it took much longer to solve, hours rather than minutes, but it came back with “infeasible”. This means that there are no Cameron-Liebler line classes of PG(3,4) with parameter 8.

No comments yet

Leave a Reply

Fill in your details below or click an icon to log in: Logo

You are commenting using your account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s


Get every new post delivered to your Inbox.

Join 54 other followers

%d bloggers like this: